KM = KG + GM KM = KB + BM GZ = KN - KG x sin ø where KN can be found from KN curves Righting Moment = Δ x GZ where Δ = displacement
KG = Total Vertical Moment of Weights about keel [metre.tonnes] Δ [tonnes] GG1 = Moment of Weight,W shifted over Distance, D [metre.tonnes] Δ [tonnes] : vertical shift of G
GG1 = Moment of Weight,W shifted over Distance, D [metre.tonnes] Δ [tonnes] : vertical shift of G
KM = KB + BM KB = 0.53 x Draft [metre] BM = 2nd moment of waterplane area = I [metre] volume of displacement V where I = L x B3 [metre4] for a rectangular barge 12
KB = 0.53 x Draft [metre]
BM = 2nd moment of waterplane area = I [metre] volume of displacement V
where I = L x B3 [metre4] for a rectangular barge 12
GM = KM - KG
VIRTUAL LOSS OF GM DUE TO FREE SURFACE
GGv = s.g. of Liquid in the Tank x I x 1 s.g. of Water in which vessel floats V n2 where GGv = virtual rise in G or deduction in G I = 2nd moment of the free surface about the centre line = L x B3 [metre4] for a rectangular compartment 12 L = Length of the Tank [metre] B = Breadth of the Tank [metre] V = Volume of the Tank [metre3] n = number of longitudinal compartments into which the tank is subdivided
where GGv = virtual rise in G or deduction in G
I = 2nd moment of the free surface about the centre line
= L x B3 [metre4] for a rectangular compartment 12
L = Length of the Tank [metre]
B = Breadth of the Tank [metre]
V = Volume of the Tank [metre3]
n = number of longitudinal compartments into which the tank is subdivided
LARGE ANGLE STABILITY - where the force of buoyancy can no longer be considered to act vertically upwards through the initial metacentre, M
GZ = (GM + ½BM.tan2 ø) sin ø : for ship's side that are "WALL-SIDED" in the vicinity of the water line
: for ship's side that are "WALL-SIDED" in the vicinity of the water line
Note:- for small angle stability, the term ( ½BM.tan2 ø) becomes negligible
∴ GZ = GM.sin ø